HOKULE‘A TO DEPART TAHITI FOR HAWAI‘I SOON

admin's picture

HOKULE‘A TO DEPART TAHITI FOR HAWAI‘I SOON

HONOLULU, Hawai‘i (January 21, 2000 – Honolulu Advertiser)---The final leg of the voyaging canoe Hokule‘a’s return from Rapa Nui is scheduled to begin later this month with a 2,655 mile trip from Tahiti to Hawai‘i.

The Hokule‘a left Hilo on the Big Island June 15, 1999, and arrived at Rapa Nui, or Easter Island, on October 8.

The canoe then set sail for Tahiti November 9 and it is expected to leave for the Big Island sometime after January 28, said Voyaging Society spokeswoman Elisa Yadao.

Master navigator Nainoa Thompson again will lead the 15-member crew, which will leave for Tahiti within the next week. Yadao said the voyage is expected to last about 28 days.

Once it reaches Hawaiian waters, Hokule‘a will anchor off of Hilo and make a second stop at Molokai. Yadao said the canoe will end its journey at Kualoa Park on Windward Oahu where a celebration is planned for March 12.

The voyage to Rapa Nui competed a series to Polynesian passages that began 25 years ago within the triangle bounded by Hawai‘i to the north, New Zealand to the south and Rapa Nui to the east.

(See: Polynesian Voyaging Society at http://leahi.kcc.hawaii.edu/org/pvs/.)

For additional reports from The Honolulu Advertiser, go to PACIFIC ISLANDS REPORT News/Information Links: Newspapers/Honolulu Advertiser.

Rate this article: 
No votes yet

Add new comment